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[y(y^3 - x)]dx + [x (y^3 + x)]dy = 0

I sense that the key factor here is (y^3 - x ) and (y^3 +x), but could not figure out how to lead the equation to

dy/dx + P(x)y = Q(x) form.

The general answer for the problem is 2xy^3 - x^2 = Cy^2.

Once I can change the equation to dy/dx + P(x)y = Q(x) form, I can do the rest (probably anybody can...)

Thanks for your help in advance.