- #1
Beez
- 32
- 0
Hello, I have tried to solve the following problem but did not succeed to do so.
[y(y^3 - x)]dx + [x (y^3 + x)]dy = 0
I sense that the key factor here is (y^3 - x ) and (y^3 +x), but could not figure out how to lead the equation to
dy/dx + P(x)y = Q(x) form.
The general answer for the problem is 2xy^3 - x^2 = Cy^2.
Once I can change the equation to dy/dx + P(x)y = Q(x) form, I can do the rest (probably anybody can...)
Thanks for your help in advance.
[y(y^3 - x)]dx + [x (y^3 + x)]dy = 0
I sense that the key factor here is (y^3 - x ) and (y^3 +x), but could not figure out how to lead the equation to
dy/dx + P(x)y = Q(x) form.
The general answer for the problem is 2xy^3 - x^2 = Cy^2.
Once I can change the equation to dy/dx + P(x)y = Q(x) form, I can do the rest (probably anybody can...)
Thanks for your help in advance.