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Homework Statement
The differential equation y + 4y^4 = (y^3 + 3x)y' can be written in differential form:
M(x,y)dx + N(x,y)dy = 0
where
M(x,y)= y+4y^4 , and N(x,y)= -y^3-3x
The term (M(x,y)dx + N(x,y) dy) becomes an exact differential if the left hand side above is divided by y^4. Integrating that new equation, the solution of the differential equation is "answer goes here" = C
Homework Equations
The Attempt at a Solution
Am I suppose to do this and integrate?
(y+4y^4-y^3-3x)/y^4 = 0
or am I off the ball completely?
Thanks!