dy/dx = (3x^2)(e^-y)(adsbygoogle = window.adsbygoogle || []).push({});

1/(e^-y) dy = 3x^2 dx

1/(e^-y) = x^3 + C

Can anybody please give me any help or advice on to where to go from here? I'm having a really tough time with this one.

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# Differential Equation

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