Solve (x^2 + y^2 - y)dx + x dy = 0 when x > 0, y > 0.
(x^2 + y^2 - y)dx + x dy = 0
The Attempt at a Solution
dy/dx = - (x^2 + y^2 - y) / x
That seems like a tricky one. Can I make it a second-order diff. eq.?
Well, with the topic we have had about vectorfields I can backwards engineer it into
F(x,y) = (x^2 + y^2 - y)i + (-x)j
But that dosn't make much sense to me.