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Differential equation

  1. Aug 1, 2008 #1
    ok so try this guy

    \lambda (\frac{dx}{dt})^{2} = (cos{ \alpha} - x)(cos{ \beta} - x)
    where x = cos{ \theta}

    and the solution is

    x = cos{ \alpha} sin^{2}{\frac{t}{2 \lambda}} + cos{ \beta} cos^{2}{\frac{t}{2 \lambda}}

    please show you're working cos that's where im getting lost

    again i think this uses weierstrass elliptic functions but i might be wrong
  2. jcsd
  3. Aug 9, 2008 #2


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    Hi latentcorpse! :smile:

    (Please don't VM me … there's no notification of VMs, and I've only just seen yours!)

    Hint: when there's sin2 and cos2, convert into cos(double):

    [tex]2x = (cos\beta\ +\ cos\alpha)\ +\ (cos\beta\ -\ cos\alpha)cos\frac{t}{\lambda}[/tex]

    Does that help? :smile:
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