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Differential equation

  1. Aug 21, 2008 #1
    Hello, I've got a problem with a differential equation...

    1. The problem statement, all variables and given/known data

    y' - ytan(x) = 2sin(x)


    3. The attempt at a solution

    I've tried to multiply the equation with the integrating factor [tex]e^{-\frac{1}{cos^{2}x}}[/tex] and then express the equation as [tex]ye^{-\frac{1}{cos^{2}x}}=\int2sin(x)e^{-\frac{1}{cos^{2}x}}dx[/tex] but then I've got lost..

    (excuse my bad English)..
     
  2. jcsd
  3. Aug 21, 2008 #2

    tiny-tim

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    Homework Helper

    Hi okhjonas! :smile:

    hmm … I thought you'd got some sleep?

    No, your integrating factor is wrong …

    you need an f with f'/f = - tanx …

    oh I see … you differentiated tanx … try integrating it!! :wink:
     
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