if y = e^(2x) . ( ax + b ), when a and b is constant find dy/dx and dee 2 y dee x squared. i already find the answer for this part and it is correct. dy/dx = e^(2x) . (2ax + 2b + a ) and dee two y dee x squared is equal to 4e^(2x) . (ax + b + a ) this is the second part of the question which im not able to solve. tried substitute the derivative value in to the equation below, but the equation is getting more complex. any hint? find values of constants p adn q such that dee two y dee x squared + p ( dy / dx ) + qy = 0 for all values of a and b any hint?