(1+x)^2 dy/dx = (1+y)^2
The Attempt at a Solution
The post I put up a while ago actually turns out to be the one above.
So far I'm not getting the right answer, please help.
But on the way, 1/(1+x^2)dx = 1/(1+y^2)dy
if I take an intergral, I get
-1/(x+1) + c = -1/(y+1) + c
This is 1/(x+1) + c = 1/(y+1) right?
The answer states that y = (1+x)/[1+c(1+x)] -1
I don't know how to get there.