- #1

- 54

- 1

## Homework Statement

dT/dt + 0.4*T - 6.4 = 0

where T is the temperature at time t

initially the temperature is 86 degrees

find the temperature at t=2.3

## Homework Equations

## The Attempt at a Solution

so i rearrange the equation to get:

dT/dt + 0.4*T = 6.4

then

integral (0.4*T) dT = integral (6.4) dt

so the general solution would be:

0.2*T^2 = 6.4*t + c

since i know that T=86 when t=0 i can work out c which i calculate to be 1479.2

so my final equation is 0.2*T^2 = 6.4*t +1479.2

but when i then put t=2.3 and solve for T my equation gives out a value of around 86.5 degrees so obviously i have gone wrong somewhere? can anyone help me out :-)