- #1

- 65

- 0

z = ((A+B)/2) + ((A-B)/2)Cos2∅ + C Sin2∅

The correct answer is

Tan2∅ = (2C)/(A-B)

- Thread starter hatchelhoff
- Start date

- #1

- 65

- 0

z = ((A+B)/2) + ((A-B)/2)Cos2∅ + C Sin2∅

The correct answer is

Tan2∅ = (2C)/(A-B)

- #2

- 24

- 0

differentiating: dz/d(theta)=0-(A-B)sin(2∅)+2Ccos(2∅)

if dz/d∅=0, then divide by cos(2∅) on both sides and you'l get

0=-(A-B)tan(2∅)+2C

solve for tan and you'll get tan(2∅)=(2C)/(A-B)

- #3

- 65

- 0

can you explain to me in more detail how you got the line

please. Its the actual process of differentiation I am having trouble with.

dz/d(theta)=0-(A-B)sin(2∅)+2Ccos(2∅)

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