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Differential equations

  1. Sep 20, 2006 #1


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    I used seperation of variables to get

    x/dx=(1-4v^2)/3v dv

    I'm not sure if thats even right.

    But if it is right, how do I integrate that?
  2. jcsd
  3. Sep 20, 2006 #2


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    Your Separation of variables looks good, now a simple substitution finishes the job.
  4. Sep 20, 2006 #3
    You made a slight mistake with the variable seperation--- you can't have dx in the denominator! (Atleast, I've learnt not to do it)
    You should have done:
    xdv = (1-4v^2)/3v dx
    dx/x = 3v/(1-4v^2) dv
    Integration from there is pretty simple.... apply your initial conditions. :)
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