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Differential equations

  • Thread starter supermesh
  • Start date
  • #1
7
0
We have these two equations:
dx/dt = -k1 (y)
dy/dt = k2 x
k1= 10 k2= 10
These are the conditions:
x(0)= 100
y(0) = 0

I am so confused.....This is what I have done so far....but is not making any sense...

x= (dy/dt) (1/k2)
Substitute in:

d2y/dt2 = -100 y

So the solution is

Y= c1 cos 10x+ c2 sin 10x

I don't know how to use boundary counditions now....Is this even a right approach?

Thank you so much
 

Answers and Replies

  • #2
458
0
The rule for a differential equation:
[tex]\frac{dy}{dt}=ky[/tex]
[tex]y(t)=y_0e^k^t[/tex]
 
  • #3
D H
Staff Emeritus
Science Advisor
Insights Author
15,329
681
x= (dy/dt) (1/k2)
Substitute in:

d2y/dt2 = -100 y
Good so far.

So the solution is

Y= c1 cos 10x+ c2 sin 10x
There is no x in your differential equation; why do you have one here? Try finding the solution to the second order differential equation again.
 

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