I am trying to solve gear ratios for a differential gearset when one of the output shaft's rotation is limited... Let's say: I have a power split device with an input (A), output1 (B) and output2 (C). C has a speed limiting mechanism attached to it. Without limiting the speed of C, ratio A:B is 2:1 and ratio A:C is 2:1. Let's apply a 300 RPM input to A without the speed limiting device engaged. B will be spinning at 150 RPM. C will be spinning at 150 RPM. Engage the speed limiter and slow C down to 75 RPM. How do I find the speed of B? My guess is C(before limiter) - C(after limiter) + B(before limiter) 150-75+150 = 225 So, the functional output gear ratio A:B after limiting C to 150 RPM would be 300/225 or 1.3333:1 I think this is right so far. Please correct me if I am wrong. If that is right, what happens if A:B does NOT equal A:C? If A:B = 3:1 and A:C = 2:1... If we apply the same 300 RPM input(without the limiter) we will have: B = 100 RPM C = 150 RPM If we slow C down to 75 RPM again how do we solve for B? If we apply C(before limiter) - C(after limiter) + B(before limiter) we get: 150 - 75 + 100 = 175 RPM @ B Therefore A:B after the limiter is engaged is 1.714:1 Is this right? It feels like there is missing something. Thanks for any help you can give.