# Homework Help: Differential K-Forms

1. Dec 6, 2011

### TranscendArcu

This is more a concept question than an actual homework problem but why is it more or less meaningless to define differential k-forms on Rn in this case of k > n?

I'm not really sure why this is so, but I might guess that since two dxis are the same in the product of such terms, then that whole term equals 0. If that's the case, is a k-form with k > n just the same as a k-form with k=n?

2. Dec 6, 2011

### HallsofIvy

Yes, that is the case but no, a k-form with k> n is not "just the same as a k-form with k= n". What is true is that there are NO k-forms with k> n. In fact, one can show that in n-dimensional space, there exist $\begin{pmatrix}n \\ k\end{pmatrix}$ k-forms.

For example, if n= 1, there exist one 0-form, the empty form, and 1 1-form, dx. If n= 2, there exist one 0-form, two 1 forms, dx and dy, and one 2 form, dxdy. If n= 3, there exist one 0-form, three 1 forms, dx, dy, and dz, three 2-forms dxdy, dydz, and dzdx, and one 3-form, dxdydz.

3. Dec 6, 2011

### TranscendArcu

Okay. Could you please show that there exist $\begin{pmatrix}n \\ k\end{pmatrix}$ k-forms, or otherwise direct me to the proof of this?

4. Dec 6, 2011

### TranscendArcu

So I found this quote that seems to explain what I'm asking about:

The only problem is that I don't know what "deg xI > n" means. What, specifically, is "deg"?

Thanks!