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Differential problem

  1. Nov 20, 2007 #1
    Hmmm its really a maths question.

    In my textbook it says - "[tex] v \frac {dv}{dx} = \frac {d}{dx} ( \frac 12 v^2) [/tex] by the chain rule."

    I can't see how they made this jump from the L.H.S. to the R.H.S.

    Last edited: Nov 20, 2007
  2. jcsd
  3. Nov 20, 2007 #2


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    Well if you differentiate the RHS w.r.t.x then you'll get [itex]\frac{1}{2}*2v\frac{dv}{dx} = v\frac{dv}{dx}[/itex] so it is really a matter of writing an equivalent statement on the RHS
  4. Nov 20, 2007 #3

    I thought [tex] \frac {d}{dx} ( \frac 12 v^2) = 2 * \frac 12 * v = v [/tex] and not [tex] v \frac {dv}{dx} [/tex]

    Sorry if im being stupid :D
  5. Nov 20, 2007 #4


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    So you're telling me that dv/dx = 1? Why do you think that?
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