Differentiate (4sinx)(cosy)=1

  • Thread starter the_ace
  • Start date
  • #1
7
0
. differentiate (4sinx)(cosy)=1 w.r.t x and fine dy/dx


Im stuck here

(4cos x)(cos y)+ (4sin x)(-sin dy/dx[y])
 

Answers and Replies

  • #2


Differentiating (4sinx)(cosy)=1 w.r.t. x:

4cos(x)cos(y)-4sin(x)sin(y)*dy/dx = 0 since the derivative of 1 is a constant.

is what you'll get, not whatever you wrote. you differentiate the whole function first, then multiply it with the derivative of the function inside.

Now, just solve for dy/dx.
 
  • #3
7
0


why its -4sin(x)sin(y)*dy....
Whts its negative 4 not PLUS!
 
  • #4


When you differentiate cos y, you get -siny. I just brought the negative sign out.
 

Related Threads on Differentiate (4sinx)(cosy)=1

Replies
10
Views
1K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
2
Views
1K
  • Last Post
Replies
1
Views
4K
Replies
5
Views
4K
Replies
6
Views
1K
  • Last Post
Replies
5
Views
4K
  • Last Post
Replies
2
Views
2K
Replies
3
Views
774
  • Last Post
Replies
3
Views
3K
Top