# Differentiate ln ln ln x^3

1. Nov 28, 2007

### BuBbLeS01

1. The problem statement, all variables and given/known data
ln ln ln x^3

2. Relevant equations

3. The attempt at a solution
My teacher was going over the review for the final and this was one of the questions. He said the answer is 1/ln ln x^3 but I don't know how to get that....can someone please help me...thank you!

2. Nov 28, 2007

### rock.freak667

y=ln ln ln x^3

Let t= lnx$^3$

so you have y= ln lnt

Let u=lnt

so you have y=lnu

by the chain rule

$$\frac{dy}{dx}=\frac{dy}{du}*\frac{du}{dt}*\frac{dt}{dx}$$