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y=x^2+4x+3/square root x
i did this
s
x^2+4x+3) square root x/ sq x * sq x
sq x *x^2)+4x*sq x+ 3/1
i did this
s
x^2+4x+3) square root x/ sq x * sq x
sq x *x^2)+4x*sq x+ 3/1
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OK, I THINK i see what you're getting at here, but I don't understand why you are multiplying sq x * sq x. If you break up each term to be over sq x, you can just then simplify the x each term, and then take the derivative. This way you don't have to do the quotient rule, you are just taking the derivative of each term separately. That is the only way I can see getting the answer you say it is supposed to be.i made all the sq x equal 1/2x^-1/2
so what am i suppost to do, i know its suppost to be 3/2 sq x + 2/sqx - 3/2x sq x
so x is imaginary?thats it, on this one u dont use the quotient rule, i could, but there's a way since square root of x is a negative number
(x^4+ 4x+ 3)/sqrt(x)= (x^4+ 4x+ 3)/x^(1/2)= (x^4+ 4x+ 3)x^(-1/2) and you can use the product rule.y=x^2+4x+3/square root x
i did this
s
x^2+4x+3) square root x/ sq x * sq x
sq x *x^2)+4x*sq x+ 3/1