Differentiate this function

Another way is to graph both your answer and the original function and see if they match up. Overall, it looks like you have a good understanding of logarithmic differentiation. Keep practicing and double-checking your work!In summary, the conversation revolves around differentiating the function [(e^x)*sin(x)]/[(x^2)*cos(x)] with respect to x using logarithmic differentiation. The original poster shared their attempted solution and asked for confirmation on its correctness. Another user pointed out a mistake and provided guidance. The summary concludes by acknowledging the original poster's understanding and suggesting ways to check their work.
  • #1
54
0
1. The problem statement
Differentiate with respect to (x) the following function...

https://www.physicsforums.com/attachment.php?attachmentid=62329&stc=1&d=1380565485

*As you can see I attempted logarithmic differentiation but am unsure if I'm doing it right at the moment. Could someone send me an image of their calculations?
 
Physics news on Phys.org
  • #2
K.QMUL said:
1. The problem statement
Differentiate with respect to (x) the following function...

https://www.physicsforums.com/attachment.php?attachmentid=62329&stc=1&d=1380565485

*As you can see I attempted logarithmic differentiation but am unsure if I'm doing it right at the moment. Could someone send me an image of their calculations?

Your attachment does not appear on my screen. Why don't you just type out the function?

Also: I don't think you should expect anyone to send you an image of their calculations. That is not supposed to be how this forum works.
 
Last edited:
  • #3
Sorry, its the following:

[(e^x)*sin(x)]/[(x^2)*cos(x)]
 
  • #5
Here is my working out so far, not sure if its correct though
 

Attachments

  • IMG_20130930_192259.jpg
    IMG_20130930_192259.jpg
    94.3 KB · Views: 363
  • #6
I see one mistake, right when you took the natural log of both sides ln(ex) = x, not xln(ex) as you have. The work below that is correct, though, so you must have intuitively used the correct value. Your answer looks fine.

One way to check your work is to use the quotient rule to see if you get the same result.
 

Suggested for: Differentiate this function

Replies
15
Views
607
Replies
17
Views
982
Replies
9
Views
158
Replies
11
Views
915
Back
Top