Differentiate this, i

  • #1
afcwestwarrior
457
0
y=ex(x is suppost to be smaller and on the top right of e)/x squared

i a suppost to differentiate this, well i wrote -2ex/x cubed+ ex/ x sq.

now u probabl might be confused by the way i wrote it since i dont know how to put the right things for my problems,

well i set up the problem how do i figure out the answer,

i know the answer but how do i figure it out
 
Last edited:

Answers and Replies

  • #2
ranger
Gold Member
1,685
2
Is this what you are getting at y = ex/x2?

Would it help if you rewrite it as a product rule:
ex.x-2
 
  • #3
cristo
Staff Emeritus
Science Advisor
8,140
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i a suppost to differentiate this, well i wrote -2ex/x cubed+ ex/ x sq.

This is correct.
 
  • #4
Gib Z
Homework Helper
3,352
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i know the answer but how do i figure it out

[tex]y=\frac{e^x}{x^2}[/tex]
Let [itex]u=e^x[/itex] and [itex]v=x^2[/itex].

By the quotient rule, the derivative is [tex]\frac{u'v-v'u}{v^2}[/tex]
 
  • #5
cristo
Staff Emeritus
Science Advisor
8,140
74
i know the answer but how do i figure it out

I must've skipped over this, and so didn't notice that you wanted to know how to get the answer!!

Well, anyway, now you've got two ways; using the product rule as shown by ranger, or the quotient rule given by Gib Z.
 

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