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Differentiating a scalar potential
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[QUOTE="RPinPA, post: 6078067, member: 651116"] What you wrote as ##V(\chi)## is equation (5) for ##dV/d\chi##, the derivative of (4) with respect to ##\chi##. What you wrote as (*) is the term in square brackets in (9), which supposedly represents ##dV/d\chi## (ignoring the constant up front as you did). Thus the authors are saying it's the same as (5), not the derivative of (5). So all they're doing is algebraic rearranging of the expression in (5), no extra differentiating happened. [/QUOTE]
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Differentiating a scalar potential
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