Differentiating exponential

  • Thread starter andrey21
  • Start date
  • #1
466
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Differentiate the following:

u = 2 (x-t2 / 3)et/3

Here is my attempt

I have to find du/dx and du/dt

du/dx = 2 (x-t2 / 3)et/3

du/dt = -4t/9 (x-t2 / 3)et/3
 

Answers and Replies

  • #2
182
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It would help if you wrote u as 2xet/3 - (2/3)t2et/3. Since u is a function of both t and x, you will have to use the chain rule in your derivatives.

For example, if v = 3m2, then dv/dx = d/dx (3m2) = d/dm (3m2) (dm/dx) = 6m dm/dx.
 
  • #3
466
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Ok so from what you have said:

u = 2xet/3 - 2/3 t2et/3

du/dx = 2/ e t/3

du/dt = 2/3 xe t/3 - 4/9 t e t/3
 
  • #4
558
1
Ok du/dx
There are errors in du/dt
 
  • #5
466
0
Ah yes I need to adopt the product rule on:

-2/3 t2 e t/3
 

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