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Differentiation defintiion

  1. Oct 5, 2011 #1
    1. The problem statement, all variables and given/known data

    when is this statement true : the derivative df/dg of the function f(g) exists

    what does this mean exactly?


    2. Relevant equations




    3. The attempt at a solution

    does it mean-

    1. df/dg represents the rate of change of f with respect to g at any given value
    of g.


    or

    2.df/dg is the ratio of two small differences, df and dg, either of which may be positive or negative.

    0r

    3.df/dg is a function, called a derivative, which is always less than the value of
    f(g) at any given value of g, that is, df/dg < f for all values of g.

    i think the solution is 1.

    because- definition of differentiation is:

    Differentiation is a method to compute the rate at which a dependent output y changes with respect to the change in the independent input x. This rate of change is called the derivative of y with respect to x. In more precise language, the dependence of y upon x means that y is a function of x.
     
  2. jcsd
  3. Oct 5, 2011 #2
    any hints?

    im i correct or incorrect!
     
  4. Oct 5, 2011 #3

    Mark44

    Staff: Mentor

    Calculus problems should be posted in "Calculus & Beyond," not in the Precalculus section.
     
  5. Oct 5, 2011 #4
    sorry
     
  6. Oct 5, 2011 #5

    Mark44

    Staff: Mentor

    To answer your question - it's 1. df/dg represents the derivative of f with respect to g.

    For example, let f(x) = 2x + 3, and g(x) = x2, and let h(x) = f(g(x)).

    Then h'(x) (or dh/dx) = d/dx[f(g(x))] = f'(g(x)) * g'(x). The expression on the left here corresponds to what your problem calls df/dg.

    Working in the example, we have h(x) = f(x2) = 2x2 + 3, so h'(x) = 4x, using a direct approach.

    Using the chain rule, we have h'(x) = f'(x2) * 2x = 2 * 2x = 4x.
     
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