What is the Derivative of Functions with Radical and Fractional Exponents?

In summary, the conversation is about differentiating with respect to x. The given equations, y= 2/ (2x+3)^4, y= x(x+1)^(1/2), y= (x +1)(x^2 + 3x)^3, and y= 3x^3 + 3x^(-1/2) + 2, are all being differentiated using various rules such as the chain rule and the product rule. The conversation also includes a question about whether the person has learned the chain rule yet and a clarification on using the power rule. One person provides their solutions for the equations and the other person questions some of the steps.
  • #1
disfused_3289
13
0
I'm having trouble with the following questions about differention with respect to x.

Differentiate with respect to x:

a)

y= 2/ (2x+3)^4

b)

y= x(x+1)^(1/2)

c)

y= (x +1)(x^2 + 3x)^3

d)

y= 3x^3 + 3x^(-1/2) + 2



Any help would be greatful
 
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  • #2
Have you learned the chain rule yet?
 
  • #3
disfused_3289 said:
a) y= 2/ (2x+3)^4
Re-write as;

[tex] y = 2(2x+3)^{-4}[/tex]

And use the chain rule.

disfused_3289 said:
b)y= x(x+1)^(1/2)
c)y= (x +1)(x^2 + 3x)^3
Chain rule and product rule

disfused_3289 said:
d) y = 3x^3 + 3x^(-1/2) + 2
Just use the power rule.
 
  • #4
Yes, I have learned chain rule

to differentiate from x you find dy/dx
 
  • #5
Here are my solutions, I don;t know if they're correct

a)

y= 2/ (2x+3)^4

= -4(2x +5)^(-5) x 2 x 2

= -16/ (2x + 5) ^ (-5)

b)

y= x(x+1)^(1/2)

= ( x + 2) (x + 1)^ (1/2) / 2

d)

y = 3x^3 + 3x^(-1/2) + 2

= 3x^2 - 3/2x^(1/3)
 
Last edited:
  • #6
disfused_3289 said:
Here are my solutions, I don;t know if they're correct

a)

y= 2/ (2x+3)^4

= -4(2x +5)^(-5) x 2 x 2

= -16/ (2x + 5) ^ (-5)
Almost, where's the +5 come from in the bracket? And are you sure that should be a -5?
disfused_3289 said:
b)
y= x(x+1)^(1/2)
= ( x + 2) (x + 1)^ (1/2) / 2
I'm not sure where your coming from with that, perhaps if you posted your steps?
 

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