- #1

chaosblack

- 16

- 0

**simple SIMPLE local extremia question**

## Homework Statement

Find the absolute maximum and absolute minimum values of f(x) = 3x^4 - 8x ^3 + 12x^2 -48x +25, where 0 <= x <= 3.

## Homework Equations

N/a

## The Attempt at a Solution

f'(x) = 12x^3 - 24x^2 + 24x -48

= 12 (x^3 - 2x^2 + 2x -4)

= 12 (x-2) (X^2 +2)

I know how to do the rest, but just wondering before I go on... What should i do with that one factor...do I omit the (x^2 +2)?

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