# Differentiation Question.

1. May 17, 2015

### Cpt Qwark

1. The problem statement, all variables and given/known data
Given $$f(x,y)=ycosx,x(t)=t^2,y(t)=sint$$

Calculate $$\frac{df((x(t),y(t))}{dt}$$
$$t∈ℝ$$

2. Relevant equations
For parametric equations I know
$$\frac{dy}{dx}=\frac{\frac{dy}{dt}}{\frac{dx}{dt}}$$

3. The attempt at a solution
So far I have found
$$\frac{∂f}{∂x}=-ysinx$$
$$\frac{∂f}{∂y}=cosx$$
$$\frac{dx}{dt}=2t$$
$$\frac{dy}{dt}=sint$$

but I'm not too sure where to go afterwards.

2. May 17, 2015

### Noctisdark

Why do you just write f(x(t),y(t)) just change x but x(t) and y(t) and you'll get f as a WHOLE function of time, all you need there is takeout the derivative :)

3. May 17, 2015

### pasmith

Apply the chain rule.

4. May 17, 2015

### Cpt Qwark

oh so just $$f(x,y)=sintcost^2$$

5. May 17, 2015

### Noctisdark

Yes, But write f(t) = sin(t)cos(t2) and pull out the derivative :3

6. May 17, 2015

### HallsofIvy

Staff Emeritus
If $f(x,y)= y cos(x)$ with $x= t^2$ and $y= sin(t)$, then, yes, $f(x)= sin(t)cos(t^2)$ and you can differentiate that.

But I think it is more likely that you expected to use the chain rule:
$$\frac{df}{dt}= \frac{\partial f}{\partial x}\frac{dx}{dt}+ \frac{\partial f}{\partial y}\frac{dy}{dt}$$

7. May 17, 2015

### vela

Staff Emeritus
It's curious why you would calculate these derivatives if you didn't have some idea already in mind about how to solve the problem. Perhaps you just weren't clear on the details. When you reached this point, a good idea would have been to consult your notes or textbook for an example like this problem to see how to put it all together.