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Firepanda

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What order differential equation is this?

In my notes i have the 2nd order differntial equation (homogeneous equation) as

y'' + py' + qy = 0

I take possible soultions in the form y = e^mx

=> (m^2 + pm + q)e^mx = 0

Then I take solutions of the equation using the quadratic forumula of m^2 + pm + q = 0?

General soultion is then y = c(1)y(1) + c(2)y(2)

Am I getting this right?

Thanks!

here do p and q both equal to 1?

What order differential equation is this?

In my notes i have the 2nd order differntial equation (homogeneous equation) as

y'' + py' + qy = 0

I take possible soultions in the form y = e^mx

=> (m^2 + pm + q)e^mx = 0

Then I take solutions of the equation using the quadratic forumula of m^2 + pm + q = 0?

General soultion is then y = c(1)y(1) + c(2)y(2)

Am I getting this right?

Thanks!

here do p and q both equal to 1?

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