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Firepanda
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What order differential equation is this?
In my notes i have the 2nd order differntial equation (homogeneous equation) as
y'' + py' + qy = 0
I take possible soultions in the form y = e^mx
=> (m^2 + pm + q)e^mx = 0
Then I take solutions of the equation using the quadratic forumula of m^2 + pm + q = 0?
General soultion is then y = c(1)y(1) + c(2)y(2)
Am I getting this right?
Thanks!
here do p and q both equal to 1?
What order differential equation is this?
In my notes i have the 2nd order differntial equation (homogeneous equation) as
y'' + py' + qy = 0
I take possible soultions in the form y = e^mx
=> (m^2 + pm + q)e^mx = 0
Then I take solutions of the equation using the quadratic forumula of m^2 + pm + q = 0?
General soultion is then y = c(1)y(1) + c(2)y(2)
Am I getting this right?
Thanks!
here do p and q both equal to 1?
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