Diffferentiation problem

1. Jun 18, 2005

JoshHolloway

$$g(t)=t\sqrt{4-t},t<3$$
$$g'(t)=t[1/2(4-t)^-1/2 (-1)]+(4-t)^1/2$$

Last edited: Jun 18, 2005
2. Jun 18, 2005

JoshHolloway

I can not figure out how to use this text stuff, forget I said anything at all.

3. Jun 18, 2005

mattmns

4. Jun 19, 2005

saltydog

You got it Josh. Here's it is in LaTex. Just click on it to see the code:

$$g^{'}(t)=\frac{-t}{2\sqrt{4-t}}+\sqrt{4-t}$$