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[tex]g(t)=t\sqrt{4-t},t<3[/tex]
[tex]g'(t)=t[1/2(4-t)^-1/2 (-1)]+(4-t)^1/2[/tex]
[tex]g'(t)=t[1/2(4-t)^-1/2 (-1)]+(4-t)^1/2[/tex]
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You got it Josh. Here's it is in LaTex. Just click on it to see the code:JoshHolloway said:[tex]g(t)=t\sqrt{4-t},t<3[/tex]
[tex]g'(t)=t[1/2(4-t)^-1/2 (-1)]+(4-t)^1/2[/tex]