Diffferentiation problem

[tex]g(t)=t\sqrt{4-t},t<3[/tex]
[tex]g'(t)=t[1/2(4-t)^-1/2 (-1)]+(4-t)^1/2[/tex]
 
Last edited:
I can not figure out how to use this text stuff, forget I said anything at all.
 

saltydog

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JoshHolloway said:
[tex]g(t)=t\sqrt{4-t},t<3[/tex]
[tex]g'(t)=t[1/2(4-t)^-1/2 (-1)]+(4-t)^1/2[/tex]
You got it Josh. Here's it is in LaTex. Just click on it to see the code:

[tex]g^{'}(t)=\frac{-t}{2\sqrt{4-t}}+\sqrt{4-t}[/tex]
 

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