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Difficult proof

  1. Feb 11, 2005 #1
    Can anyone proove why [tex]{x^n} /\sum_{0}^{x}x^{n-1}={x-1}/x [/tex]
     
    Last edited: Feb 11, 2005
  2. jcsd
  3. Feb 11, 2005 #2

    dextercioby

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    Could you rewrite,please ??

    Daniel.
     
  4. Feb 11, 2005 #3
    Rewrite done.
     
  5. Feb 11, 2005 #4

    dextercioby

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    It doesn't look sound to me.If you sum over "x",why doesn't "n" appear in the equation...?

    Daniel.
     
  6. Feb 12, 2005 #5

    xanthym

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    Also, in its current form, the Right Side is 0 at x=(1), whereas the Left Side is non-zero at x=(1).
     
  7. Feb 12, 2005 #6

    dextercioby

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    There's definitely something weird with this exercise.Maybe he'll explain it,or or just drop it...

    Daniel.
     
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