I know:(adsbygoogle = window.adsbygoogle || []).push({});

[tex]\sum_{n=0}^\infty \frac{x^n}{n!}=e^x [/tex]

However, is there a similar solution for:

[tex]\sum_{n=0}^\infty \left(\frac{x^n}{n!}\right)^2 [/tex]

Thanks in advance; I'm not very good at this kind of maths (I teach statistics ), and I've been struggling with this one for a while.

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# Difficult series

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