# Difficult series

1. ### m00se

1
I know:

$$\sum_{n=0}^\infty \frac{x^n}{n!}=e^x$$

However, is there a similar solution for:

$$\sum_{n=0}^\infty \left(\frac{x^n}{n!}\right)^2$$

Thanks in advance; I'm not very good at this kind of maths (I teach statistics ), and I've been struggling with this one for a while.

Last edited: Dec 10, 2009