The Erdos-Straus Conjecture proposes that: For n >= 1, 4/n = 1/a + 1/b + 1/c, has postive integer solutions. n = 2k (evens) n = 4k+3 (odds) n = 4k+1 (odds) For 2k I have found the pattern --> if k >= 1, 4/2k = 1/2k + 1/2k + 1/k. This is simple, I know. I am having difficulty finding the pattern for 4k+3 (no pattern has yet been found for 4k+1, I know). So what is the pattern for: 4/4k+3 = 1/a + 1/b + 1/c ? Does anyone know this pattern? If you do, please reply with such pattern. Thank you J.E.H.