1. The problem statement, all variables and given/known data A system of 8 slits, each separated from its neighbour by 0.05 mm, is illuminated with light of wavelength 576 nm. Using phasor analysis, evaluate at what angle on a distant screen there is the first minimum in intensity. 2. Relevant equations 3. The attempt at a solution Ok firstly, I'm not at all comfortable with phasor diagrams as I don't really understand them so I've tried to go about this a different way. My thinking is that dsin(theta) = (2n-1)/2 x wavelength . I got this by thinking that if the extra distance travelled is a multiple of half a wavelength there will be destructive interference. Now by using n =1 and d= 0.05 I do not get the correct answer for theta(I have taken into account unit conversions), I know this is straightforward. Help would be much appreciated!