- #1

- 17

- 0

• Red laser

• detection screen

• the two unknown diffraction gratings

describe what difference you would observe.

n = d sin(theta)

d=1/5*105 = 2*10-6

d=1/1*106= 10-6

I don’t know how to start can someone give me any idea about this question

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- Thread starter salsabel
- Start date

- #1

- 17

- 0

• Red laser

• detection screen

• the two unknown diffraction gratings

describe what difference you would observe.

n = d sin(theta)

d=1/5*105 = 2*10-6

d=1/1*106= 10-6

I don’t know how to start can someone give me any idea about this question

- #2

- 233

- 1

If you had a screen, say, 10 m away from the 5000 line grating, how far would the central maximum be from the first, second and nth maximas? What about for the 10000 line grating?

- #3

- 110

- 0

You missed a [tex]\lambda[/tex] in your equation. It should read

[tex] n \lambda = d sin(\theta) [/tex]

Anyway, what do you expect the difference between the interference patterns to be when you shine the laser on the two different gratings? Where is the first order (n=1) maximum with each grating?

Edit:

And I see oedipa maas just posted similar remarks. . .

[tex] n \lambda = d sin(\theta) [/tex]

Anyway, what do you expect the difference between the interference patterns to be when you shine the laser on the two different gratings? Where is the first order (n=1) maximum with each grating?

Edit:

And I see oedipa maas just posted similar remarks. . .

Last edited:

- #4

- 17

- 0

suppose the wavelength= 1cm = 1*10^-9

and m= 1

when d= 2*10^-6 m/line

theta= 0.029

when d= 10^-6

theta= 0.057

that's all what i got

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