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Diffraction Grating

  • Thread starter rojasharma
  • Start date
66
0
light wavelengths of 520nm and 630nm passes through a diffraction grating that contains 6000lines/cm. a) sketch a diagram of the image produced from m=0 to m=2. label the order of each fringe.b) calculate the angles for the first and second-order maxima that would appear on the screen. c) What is the lowest value of m for which the 520-nm line no longer exists? I have no idea how to do this question:(..
 

Answers and Replies

66
0
i still don;t get it :(
 
83
1
i still don;t get it :(
you have all the data u want...
For (1) , there is a central maximum at theta =0 where the two rays coincide...
and the greater the wavelength , the greater the theta the ray is for the same order...
(sin function is increasing between 0 to pi/2)
(2) sintheta = nlamda/d
you have the slit separation , lamda and n , so it is possible to calculate


c) No longer exist when sin theta >1
 
66
0
the picture will be similar to the one shown in the website?..do i need to use protractor for that?
 
83
1
the picture will be similar to the one shown in the website?..do i need to use protractor for that?
sketch.... I don't think you need to do that:devil:
 
66
0
label the order of each fringe? what does this mean?
 
66
0
for part b) sintheta=mlmbda/d....do i use both wavelengths? or a difference of the wavelengths?....confused:S
 

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