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This problem is unfamiliar to me, I'm not sure if the eqtion I used is correct

a= lambda*length/d= (550e-9m)*(24e+3m)/5.48e-2m= 0.241m

- Thread starter lovelylm1980
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- #1

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This problem is unfamiliar to me, I'm not sure if the eqtion I used is correct

a= lambda*length/d= (550e-9m)*(24e+3m)/5.48e-2m= 0.241m

- #2

Chi Meson

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YOu have the general idea already, but for circular aperatures, there is a factor of 1.22 that is multiplied to the wavelength.

By the way, anyone, where does this 1.22 come from?

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got it thanks

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Integral

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The computation involves summing intensity contributions from each point of the aperture accounting for path length differences.

In

The theory of Fraunhofer diffraction by a circular aperture requires more elaborate mathematical computations then that of the Fraunhofer diffraction by a rectangular aperture

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Chi Meson

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So the math involve in producing this factor of 1.22 is absurdly difficult?Integral said:InOpticsby Rossi 6 pages are committed to doing this computation for a rectangular aperture. For a circular aperture he simply presents the results and comments

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Integral

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I do not think it is absurdly difficult, it requires setting up and evaluating an involved integral. Rossi must have felt that going through the process for the simpler case, of a rectangular aperture, was more productive then doing the same math only more difficult integrals.Chi Meson said:So the math involve in producing this factor of 1.22 is absurdly difficult?

I am sure that if you searched through enough optics texts you will find it worked out some where.

I have the tools to figure it out in Rossi, but frankly it would take more time then I have to commit to it now.

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Chi Meson

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Integral

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My thoughts exactly. We have some common ground!Chi Meson said:

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