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Diffraction of light question

  • Thread starter Sabrina_18
  • Start date
  • #1

Homework Statement


How many orders of diffraction will be visible if light of wavelength 500nm fals on a grating with 600 000 lines per metre?


Homework Equations



n = dsinѲ / λ


The Attempt at a Solution



n = 6X10⁵m ÷ 5 X 10ˉ⁷m = 1.2
So 1 order of diffraction will be visible is this right??

I don't have the angle so I could put it into the equation.
 
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Answers and Replies

  • #2
Redbelly98
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Note that d is really (1/600,000) m, so that 600,000 lines would fit in 1 m.
 
  • #3
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Another way to pose this question is: how many maxima do you see between theta=0 and theta=90 degrees?

Consider that for a maximum to appear on the wall or the screen in front of the grating the angle theta can never be more than 90 degrees. (Recall that sin(theta) ~ (distance of nth maxima from the 0th maxima)/(distance of the grating from the screen).)
 
  • #4
Thanks for your help. Here is my improved answer:
λ = 500nm = 5 X 10ˉ⁷m
d = 6 X 10⁵ per metre = 1 ÷ 6 X 10⁵ = 16.7 X 10ˉ⁷m
n = 16.7 X 10ˉ⁷ X sin 90 ÷ 5 X 10ˉ⁷ = 3.34
There will be 3 orders of diffraction visible

Is this correct? If not please tell me where I am going wrong

Thanks
 
  • #5
Redbelly98
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Looks good. Problem solved :smile:
 

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