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Homework Help: Diffraction Problem

  1. Mar 6, 2005 #1
    Q. A He-Ne laser of wavelength (633nm) shines thru a single slit of unknown width D on to screen 2.0m away from the slit. The distance on the screen between the m = 1 minima on either side of the central maximum of the diffraction pattern is measured and is found to be 2.3 cm. What is the width of the slit?

    Ans. I did,
    ym = wavelength * D/d

    Is this right.

    Please help, me folks.......
     
  2. jcsd
  3. Mar 6, 2005 #2

    xanthym

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    Science Advisor

    {Distance From Central Maximum To First Minimum On Screen} = M =approx= λY/D
    where "λ" is the wavelength, "Y" the distance to screen, and "D" the single slit width. For this problem, we are given {λ = 633e(-9) m}, {Y = 2 m}, {M = (2.3 cm)/2 = 0.0115 m}, so that:
    D = λY/M = {633e(-9)}*(2)/(0.0115) = {1.1e(-4) m} = (110 μm)


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    Last edited: Mar 6, 2005
  4. Mar 6, 2005 #3
    if you are confused about that i think that he used:

    dsin(theta)=m*lambda
    and for small theta
    sin(theta)=tan(theta)
    and in this case, tan(theta)=Size projected on screen/distance to screen
     
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