# Diffrenetiating cos(yz^2)

1. Jan 30, 2012

### JamesGoh

To differentiate $cos(yz^{2})$ with respect to y

can we simply ignore the $z^{2}$ term in the differentiation ?

2. Jan 30, 2012

### Pythagorean

yup! since it's with respect to y, z is irrelevant.

3. Jan 30, 2012

### HallsofIvy

Staff Emeritus
Do not "ignore" it, treat it like a constant!

4. Jan 31, 2012

### oferon

treat it like a=z^2.. It's a constant when differentiating with respect to y