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Diffrenetiating cos(yz^2)

  1. Jan 30, 2012 #1
    To differentiate [itex]cos(yz^{2})[/itex] with respect to y


    can we simply ignore the [itex]z^{2}[/itex] term in the differentiation ?
     
  2. jcsd
  3. Jan 30, 2012 #2

    Pythagorean

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    yup! since it's with respect to y, z is irrelevant.
     
  4. Jan 30, 2012 #3

    HallsofIvy

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    Do not "ignore" it, treat it like a constant!
     
  5. Jan 31, 2012 #4
    treat it like a=z^2.. It's a constant when differentiating with respect to y
     
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