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Dillution of a gas

  1. Mar 4, 2009 #1
    1. The problem statement, all variables and given/known data
    Nitrogen dioxide reacts with water in the atmosphere to produce acid rain.
    4N02(g)+2H20(g)+O2(g)------> 4HNO3(g)
    assuming that the temperature and the pressure remain constant, calculate the volume of air at 1 atm, 20oC, necessary to dilute the HNO3(g) to 0.050 ppm(by volume) when 560.g of NO2(g) is allowed to react.


    2. Relevant equations

    V=nRT/P where n=number of moles, R=ideal gas constant, T=temperature, P= pressure


    3. The attempt at a solution

    First calculate the volume of HNO3 gas that will be produced. then using the equation a/b=c/d
    I calculated the volume required to dilute

    .050L/1,000,000L = 292.808L / V

    solve for V and I got 5.9 x 10^9 L
     
    Last edited: Mar 4, 2009
  2. jcsd
  3. Mar 5, 2009 #2

    Borek

    User Avatar

    Staff: Mentor

    Looks OK.
     
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