Dimension magnetism problem

1. Aug 16, 2007

In magnetism ,
mH = F, where m = pole strength ; H= magnetic field intensity ; and
F = Force.

F = [ MLT$$^{}-2$$]

Proof that dimension of mH = [MLT$$^{}-2$$]

2. Aug 16, 2007

hage567

Can you figure out the dimensions from the units of m and H? What are you not understanding? You didn't really ask a question.

3. Aug 16, 2007

Nesk

If you wish to proove from F=mH that mH has dimensions of MTL-2, just consider that mH is equal to a force, which is equal to mass times acceleration: M*LT-2.

This is not as much an excercise in magnetism as in rather basic dimensional analysis.

Last edited: Aug 16, 2007