Dimensional Analysis Problem

In summary, the American Petroleum Institute has published a correlation for determining hydrocarbon emissions from fixed-roof storage tanks. The formula includes variables for breathing emissions, true vapor pressure, tank diameter, height, average tank outage, paint factor, and adjustment factor. However, there is a doubt about one of the terms being dimensionally consistent due to the presence of a unitless constant and a pressure in psia. This formula should not be treated as an equation and cannot be easily translated to work with different units.
  • #1
popoff
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Homework Statement


The American Petroleum Institute has published a correlation for determining the hydrocarbon emissions from fixed-roof storage tanks

Ly = (24/1000) * (p/(14.7-p))^0.68 * D^1.73 * H^0.51 * T^0.5 * Fp * C

where: Ly is breathing emissions, bbl/yr; p is the true vapor pressure at the bulk temperature, psia; D is the tank diameter, ft; H is the height in ft; T is the average tank outage corrected for roof volume, ft; Fp is the dimensionless paint factor; and C is the dimensionless adjustment factor.

Is this equation dimensionally consistent?

Homework Equations


Unit conversions

The Attempt at a Solution


I have a doubt with the (p/(14.7-p))^0.68 term. I think it should be dimensionless, but I am not totally sure as there is a 14.7 with no units minus a pressure in psia...
 
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  • #2
popoff said:
... as there is a 14.7 with no units minus a pressure in psia...
What is atmospheric pressure in psi?
 
  • #3
popoff said:
I have a doubt with the (p/(14.7-p))^0.68 term. I think it should be dimensionless, but I am not totally sure as there is a 14.7 with no units minus a pressure in psia...
It's terms like that that indicate that this is not an equation, but a formula. There are many such formulas for different disciplines, typically compiled into handbooks, where you must enter the variable values as dimensionless magnitudes of quantities that are given in specific units. A formula is "true" only so long as you specify all quantities in the required units and don't entry the units :smile:

A formula's constants typically have no units so you can't trivially "translate" the formula to work with other units, and since you have to interpret the result of the formula in particular units you can't just treat the expression as an equation and "solve" for any of the variables in terms of the others without putting some thought into what you're doing.
 

1. What is dimensional analysis?

Dimensional analysis is a problem-solving method used in the fields of physics and chemistry to convert units of measurement. It involves using conversion factors and unit cancellation to solve problems and ensure that units are consistent throughout calculations.

2. Why is dimensional analysis important?

Dimensional analysis is important because it helps scientists and researchers to accurately convert units and solve complex problems without making mistakes. It also ensures that the units used in calculations are appropriate for the given situation.

3. How is dimensional analysis used in scientific research?

Dimensional analysis is used in scientific research to convert units and ensure that measurements are consistent throughout experiments and calculations. It is especially useful in fields such as physics, chemistry, and engineering, where precise measurements and calculations are crucial.

4. What are the steps involved in solving a dimensional analysis problem?

The first step in solving a dimensional analysis problem is to identify the given quantity and the desired quantity, and then determine the conversion factor needed to convert between them. Next, set up the problem using the conversion factor and the given values, making sure to cancel out units as needed. Finally, perform the calculation and convert the answer to the desired units.

5. Can dimensional analysis be used for any type of unit conversion?

Yes, dimensional analysis can be used for any type of unit conversion as long as the units involved are related by a conversion factor. This method is particularly useful for converting between metric and imperial units, as well as for more complex unit conversions involving multiple units.

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