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Dimensional analysis question

  1. Sep 12, 2005 #1
    The piston displacement of a car engine is given as 1.80 liters (L). Using only the facts that 1.00L = 1000 cm^3 and 1.00 in. = 2.54 cm, express this volume in cubic inches. So [tex] 1.80 L \times (\frac{1000 cm^{3}}{1.00 L})(\frac{1.00 in}{2.54 cm}) [/itex]. Would I have to cube the last term to cancel out the units?

  2. jcsd
  3. Sep 12, 2005 #2


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    Yes. Cube the whole last proportion- (1.00in./2.54cm)^3. Remember, Your looking for cubic inches as well. There your solving for only inches.
  4. Sep 12, 2005 #3
    Yup. Whenever you convert units to a power, both sides of the convertion must be to the same power.

    The answer should end up being aroung 16.8 IIRC, converting CC to cu. in. (I'm a car fanatic, and do these calculations often when figuring muscle car engines)
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