Dimensional Analysis: Finding Relation Between v, p and p

In summary, the velocity of sound, v, in a gas can be expressed as a function of the gas density, ρ, and pressure, p, using dimensional analysis. By equating the dimensions of the two sides of the equation, we can determine the powers, α and β, that relate the variables.
  • #1
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Homework Statement


The velocity,v of the sound in a gas depends on the density, p and the pressure, p of the gas. By using dimensional analysis, find a possible relation between v, p and p.


Homework Equations


[v] = LT-1
[p] = ML-3
[p] = ML-1T-2


The Attempt at a Solution


well i have no idea how to do it, so far i can only express the variables in dimension ways
 
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  • #2
Here, have a ρ to express the density.

The whole concept of dimensional analysis is based on the fact that you can only equate two quantities if they have the same dimensions and units.

You are told that the velocity of sound in a gas, [tex]v[/tex] depends on two factors, that is to say, that it is a function of these two factors.

[tex]v=f(\rho , p)[/tex]

Naively, we say that it is a product of these two quantities, raised to some powers [tex]\alpha, \beta[/tex]:

[tex]v=\rho^{\alpha}\cdot p^{\beta}[/tex]

Now use dimensional analysis to find [tex]\alpha, \beta[/tex]

Do this by constraining the system so that the dimensions on the RHS are the same as the dimensions on the LHS.
 
  • #3
, such as v = LT-1, p = ML-3, and p = ML-1T-2. However, by using dimensional analysis, we can manipulate these equations to find a relationship between v, p, and p. This can be done by setting up a dimensional equation with the given units and using algebraic manipulation to solve for the unknown relationship. In this case, we can write:

v = k p^a p^b

Where k is a constant and a and b are exponents to be determined. By equating the dimensions on both sides, we get:

LT^-1 = (ML^-3)^a (ML^-1T^-2)^b

Simplifying, we get:

LT^-1 = M^(a+b) L^(-3a-b) T^(-2b)

Equating the powers of M, L, and T on both sides, we get the following system of equations:

a + b = 0
-3a - b = -1
-2b = -1

Solving for a and b, we get:

a = 1/2
b = -1/2

Therefore, the relationship between v, p, and p is:

v = kp^(1/2)p^(-1/2)

Or, simplifying:

v = kp^0

v = k

This means that the velocity of sound in a gas is directly proportional to a constant k, independent of the density and pressure of the gas. In other words, the velocity of sound in a gas is constant as long as the gas remains in the same state. This relationship can also be verified experimentally by measuring the velocity of sound in different gases at the same pressure and density.
 

1. What is dimensional analysis?

Dimensional analysis is a mathematical technique used to convert units from one system to another. It involves identifying the physical quantities involved in a problem and using their units to create conversion factors, ultimately allowing for the conversion of units from one system to another.

2. How is dimensional analysis used to find the relation between velocity, pressure, and density?

Dimensional analysis can be used to find the relationship between velocity (v), pressure (p), and density (p) by setting up equations with units for each quantity and solving for the desired relationship. For example, the equation for pressure (p) is force (F) divided by area (A), so the units for pressure would be units of force per units of area. By manipulating the units for velocity and density in a similar way, we can find their relationship to pressure.

3. Why is dimensional analysis important in science?

Dimensional analysis is important in science because it allows for the conversion of units, which is crucial in making accurate measurements and calculations. It also helps to identify any errors in units and ensures that equations and relationships between physical quantities are consistent.

4. Can dimensional analysis be used for all types of physical quantities?

Yes, dimensional analysis can be used for all types of physical quantities as long as the units for each quantity are known. It is a versatile technique that can be applied to various fields of science, including physics, chemistry, and engineering.

5. How can dimensional analysis be used to check the validity of an equation?

Dimensional analysis can be used to check the validity of an equation by ensuring that the units on each side of the equation are consistent. If the units on each side are not equal, then there is likely an error in the equation or a missing conversion factor. This technique is often used in scientific research to verify the accuracy of equations and relationships between physical quantities.

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