- #1
transgalactic
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there is a matrix A of M3X3 (K) over field K
so rank A=r , marked U as A of M3X3 (K) so AX=0
prove that dim U=3(3-r))
??i was told that each column gives me 3-r we have 3 columns so
it 3(3-r)
i can't understand how we get 3-r out of each column??
there is W={x exists in R^3|Ax=0}
dim W=3-r
1-1 function hase Ker (t)=0
Im (T)=WxWxW
i understand that W is the kernel of T
then they say
"dim W=3-r"
so '"r" is the Image of the matrix
but why its from one column
??
so rank A=r , marked U as A of M3X3 (K) so AX=0
prove that dim U=3(3-r))
??i was told that each column gives me 3-r we have 3 columns so
it 3(3-r)
i can't understand how we get 3-r out of each column??
there is W={x exists in R^3|Ax=0}
dim W=3-r
1-1 function hase Ker (t)=0
Im (T)=WxWxW
i understand that W is the kernel of T
then they say
"dim W=3-r"
so '"r" is the Image of the matrix
but why its from one column
??
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