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Dinner or diner ?

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  1. Sep 9, 2015 #1
    1. The problem statement, all variables and given/known data

    How many different permutations can be created with the word dinner ?
    2. Relevant equations


    3. The attempt at a solution
    Well if we consider all the permutations it will be
    6P6 = 6*5*4*3*2*1 = 720 combinations --6!--
    If we consider the distinguishable ones
    Since 2N 's are present we can write as "diner" as it wont make a difference to the permutation and write as 5*4*3*2*1 =120 combinations does this make sense?
     
  2. jcsd
  3. Sep 9, 2015 #2
    My opinion:
    The permutation of two 'n' doesn't make different, so the numbers of the permutation ##2!=2## can be regarded as one type. So, the answer should be ##\frac{6!}{2!}=360.##
     
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