# Homework Help: Dinner or diner ?

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1. Sep 9, 2015

### #neutrino

1. The problem statement, all variables and given/known data

How many different permutations can be created with the word dinner ?
2. Relevant equations

3. The attempt at a solution
Well if we consider all the permutations it will be
6P6 = 6*5*4*3*2*1 = 720 combinations --6!--
If we consider the distinguishable ones
Since 2N 's are present we can write as "diner" as it wont make a difference to the permutation and write as 5*4*3*2*1 =120 combinations does this make sense?

2. Sep 9, 2015

### tommyxu3

My opinion:
The permutation of two 'n' doesn't make different, so the numbers of the permutation $2!=2$ can be regarded as one type. So, the answer should be $\frac{6!}{2!}=360.$