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## Homework Statement

See attachment

## Homework Equations

We are to assume the voltage drop across diodes is .7v (don't use the diode equation!).

## The Attempt at a Solution

I first was assuming that both diodes were "on". Then my work is as follows:

V1 is the voltage directly above diode D1 (the left most diode)...

[tex]I+ \frac{V_{1}-.7-(-5)}{5k\Omega}=\frac{5-V_{1}}{10k\Omega}[/tex]

[tex]I+ \frac{.7-.7+5}{5k\Omega}=\frac{5-.7}{10k\Omega}[/tex]

[tex]I=-.57mA[/tex]

Now since I is negative, one of my assumptions is wrong? So now I assume the rightmost one is "off" (D2).

So.. then

__Solving for I__

[tex]I = \frac{5-.7}{10k\Omega}[/tex]

[tex]I = .43 mA[/tex]

__Solving for V__

Well.. since theres no current, v=-5?

Am I approaching this correctly?

#### Attachments

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