I wanted to post a similar looking circuit but I couldn't find any, so I'll have to describe it unfortunately. Imagine a circuit where you have two resistors and you want to measure the voltage across each of those resisistors so you put a voltmeter parallel to each one. Except, instead of voltmeters, imagine diodes with one facing the current and the other facing opposite. The source pd is 3V with negligable internal resistance, the forward facing diode is parallel to a 10Kohm resistor and the reverse facing diode is parallel to a 5k resistor. We want to know the pd and current for each resistor and diode, and then what the pds and currents would be if the diodes were reversed 2. Relevant equations V= IR, Kirchoff 1st and 2nd law, forward diodes have pd of 0.6V... 3. The attempt at a solution the pd is 3V for each diode and resistor? (incorrect) the pd is 0.6V for the forward facing diode (correct) so the pd for the parallel 10K resistor is 2.4V (incorrect) I know that voltmeters have a very high resistance so that they can read a pd as close to what the resitor's pd is and so the diode with its very high resistance in the reverse would read the same pd as the parallel 5k resistor. However I still can't work that out as I don't know the current for the circuit, And I can't can't work out the current because I don't what the total resistance is because I don't know what the resistance of the forward diode is. I've tried alot of algebra but can't get anywhere.