1. The problem statement, all variables and given/known data But-2-ene-1,4-diol is converted in two steps through an intermediate X into ketobutanedioic acid. Hot acidified KMnO4 is added in step 2. HOCH2CH=CHCH2OH ----> X -----> HO2CCOCH2CO2H What could be the reagent for step 1 and the intermediate X? reagent for step 1 X A cold acidified KMnO4 HOCH2CH2CH(OH)CH2OH B hot acidified KMnO4 OHCCH(OH)CH2CHOC steam and concentrated H2SO4 HOCH2CH(OH)CH2CH2OH D warm acidified K2Cr2O7 HO2CCH=CHCO2H Sorry about the unalignment. 3. The attempt at a solution I'm aware that an alkene reacts with cold KMnO4 to give a dol and hot KMnO4 to give a dicarboxylic acid but I'm stumped since the first compound is both a diol and alkene. Any help appreciated!