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Diophantine Equation a(3b+1)=c

  1. Sep 13, 2010 #1
    The solutions are obvious. I want to know if there is a solution a(n), b(n) (and so, c(n)) or at least a solution a(b).
    Can someone help with that..?
    Last edited: Sep 13, 2010
  2. jcsd
  3. Sep 13, 2010 #2
    Sorry.. I didn't explain before.
  4. Sep 15, 2010 #3
    What do you mean by "a(n), b(n) (and so, c(n))" ?
  5. Sep 15, 2010 #4
    I mean a solutions in one variable. Like (2n, n²-1,n²+1) is a solutioin for x²+y²=z²
  6. Sep 16, 2010 #5
    There are an infinite number. The only comprehensive one of all possibilities though is
    a = F(n), b = G(n), so c= F(n)*(3G(n)+1). Simple as that.
    Last edited: Sep 16, 2010
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